the ratioof lenght to breadth of a rectangular Field is4:3. If it's diagonal is 200m, the area of the field in s
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4
Given:
The ratio of length and breadth of a rectangular field is 4:3
The diagonal of the rectangular field = 200 m
Find:
Area of the field
Solution:
Let 'x' be the common in given ratios
Length = 4x
Breadth = 3x
Pythagoras theorem:-
(Hypotenuse)² = (Base)² + (Perpendicular)²
=> (200)² = (3x)² + (4x)²
=> 40000 = 9x² + 16x²
=> 40000 = 25x²
=> 40000/25 = x²
=> 1600 = x²
=> √1600 = x²
=> 40 = x
=> x = 40
So,
- Length = 4x = 4(40) = 160
- Breadth = 3x = 3(40) = 120
Now,
Area of Rectangle = Length × Breadth
=> 160 ×120
=> 19200m²
Hence, the area of rectangular field is 19200 m².
I hope it will help you.
Regards.
Answered by
1
let the length and breadth be 4x and 3x respectively .
According to the question
diagonal = √ l²+b²
200= √(4x)²+(3x)²
200 = √16x²+9x²
200 = √25x²
200= 5x
x= 200/5 = 40
x= 40
hence length and breadth are 4x = 4×40 = 160 and 3x = 3×40 = 120m respectively.
Area of rectangle =
length×breadth
= 160×120
= 19200cm²
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