The ratios of height of two cylinders is 3:2 and the ratio of their radius is 6:7. What is the ratio of their
curved surface area ?
Answers
Answer:
Let r 1 and r 2 be the radii of the cylinders respectively.
⇒
r1/r2 = 6/7
Let h 1 and h 2 be the heights of the cylinders respectively.
⇒ h 1/h2 =3/2
Ratio of Curved surface areas= (2πr 1h1)/(2πr2h2)
=(r1h1)/(r2h2)
= ( 6×3)/(7×2)
=18/14
=9/7
Hence,ratio of their curved surface area is 9:7
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Ratio in their heights
=
5
:
3
Let
r
1
and
r
2
be the radii and
h
1
,
h
2
be their heights respectively.
∴
r
1
:
r
2
=
2
:
3
and
h
1
:
h
2
=
5
:
3
∴
r
1
r
2
=
2
3
and
h
1
h
2
=
5
3
Since, Surface area of the first cylinder
=
2
π
r
h
square units
⇒
The ratio of surface area of the two cylinders
=
2
π
r
1
h
1
2
π
r
2
h
2
=
r
1
h
1
r
2
h
2
=
r
1
r
2
×
h
1
h
2
=
2
3
×
5
3
=
10
9
Hence, the ratio in their surface areas
=
10
:
9
hope it will be helps u