The reaction of toluene with Cl₂ in presence of
FeCl₃ gives 'X' and reaction in presence of
light gives ‘Y’. Thus, ‘X’ and ‘Y’ are :
(a) X = Benzal chloride,
Y = o – Chlorotoluene
(b) X = m – Chlorotoluene,
Y = p –Chlorotoluene
(c) X = o –and p – Chlorotoluene,
Y = Trichloromethyl – benzene
(d) X = Benzyl chloride,
Y = m – Chlorotoluene
Answers
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Answer:
C is the answer as we get o & p chlorotoulene
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(c) X = o –and p – Chlorotoluene,
Y = Trichloromethyl – benzene
Explanation:
The reaction of Cl2, in presence of FeCl3, with benzene yields a ring substitution product. In presence of sunlight, free radical reaction takes place. In the presence of FeCl3, toluene reacts with Cl2 to give ortho and para chlorotoluene. It is an electroscopic substitution reaction.
This X in the presence of light, substitution happens in the methyl group rather than the ring. So trichloromethylbenzene is formed, which is Y.
Option C is the answer.
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