The reaction time for an automobile driver is 0.5 s. If the automobile can be decelerated at 4m/s^2 , calculate the total distance travelled in coming to stop from an initial velocity of 30 km/hr , after a signal is observed.
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-a = -4m/s^2
t = o.5 sec
s =?
v = om/s
u = 30 km/ hr = 8.33 m/s
S = ut + 1/2 at^2
= 8.33 × 0.5 + 1/2 × -4 × (0.5 )^2
= 4.165 - 2 × 0.25
= 4.165 - 0.5
= 3.665
t = o.5 sec
s =?
v = om/s
u = 30 km/ hr = 8.33 m/s
S = ut + 1/2 at^2
= 8.33 × 0.5 + 1/2 × -4 × (0.5 )^2
= 4.165 - 2 × 0.25
= 4.165 - 0.5
= 3.665
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