Physics, asked by chandrsekhar72, 1 year ago

the rectangular components of force of 13N are​

Answers

Answered by ishucutee
1

Hello!!!!!!

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The rectangular components of 13 N are

(i) 13 sin theta ___ the other one which is perpendicular to the force 13N

(ii) 13 cos theta __ which makes angle theta with the force of 13N

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Answered by soniatiwari214
1

Concept:

  • Vector addition
  • Splitting a vector into its horizontal and vertical components
  • Force is a vector quantity, it has both magnitude and direction
  • We will also apply Pythagoras' Theorem
  • x and y components of the vector are the rectangular components

Given:

  • The force has a magnitude of 13 N
  • F = 13 N

Find:

  • The horizontal component x and vertical component y of the force vector

Solution:

  • F = vector addition of x and y component
  • F = √(x²+y²)
  • 13 = √(x²+y²)
  • 13² = x²+y²
  • 169 = x²+y²
  • 169 = 25 +144
  • 25 = 5², 144 = 12²
  • 13² = 5² + 12²

The rectangular components of the force of 13 N are 5 N and 12 N.

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