the rectangular components of force of 13N are
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The rectangular components of 13 N are
(i) 13 sin theta ___ the other one which is perpendicular to the force 13N
(ii) 13 cos theta __ which makes angle theta with the force of 13N
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Concept:
- Vector addition
- Splitting a vector into its horizontal and vertical components
- Force is a vector quantity, it has both magnitude and direction
- We will also apply Pythagoras' Theorem
- x and y components of the vector are the rectangular components
Given:
- The force has a magnitude of 13 N
- F = 13 N
Find:
- The horizontal component x and vertical component y of the force vector
Solution:
- F = vector addition of x and y component
- F = √(x²+y²)
- 13 = √(x²+y²)
- 13² = x²+y²
- 169 = x²+y²
- 169 = 25 +144
- 25 = 5², 144 = 12²
- 13² = 5² + 12²
The rectangular components of the force of 13 N are 5 N and 12 N.
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