The rectangular field is to be fenced. The length of the field is 16 m more than the width. if 140 m of fencing is required find the dimensions of the field?
Answers
Answered by
10
Hey,
Your Answer is Here,
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Let the width to be x
and the length to be (x+16)
NOW,
Perimeter of Rect. Field = Fencing
2(Length+Breadth) = 140
2(x+16+x) = 140
2x+16 = 140/2
2x = 70-16
x = 54/2
x = 27
Width = x = 27m
Length = x+16 = 27+16 = 43m
---------------------------------------------------------------------------------------------------
(I HOPE IT HELPS YOU)
MARK AS A BRILLIANT
Your Answer is Here,
------------------------------------------------------------------------------------------------------
Let the width to be x
and the length to be (x+16)
NOW,
Perimeter of Rect. Field = Fencing
2(Length+Breadth) = 140
2(x+16+x) = 140
2x+16 = 140/2
2x = 70-16
x = 54/2
x = 27
Width = x = 27m
Length = x+16 = 27+16 = 43m
---------------------------------------------------------------------------------------------------
(I HOPE IT HELPS YOU)
MARK AS A BRILLIANT
harpal79:
thanks
Answered by
1
Answer:ok
Step-by-step explanation:
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