Biology, asked by nyogesh1304, 11 months ago

The reducing agent is NADH+H+ which is reoxidised to NAD+ in which processes?​

Answers

Answered by yashdhawaj
0

Answer:

hi mate

Explanation:

nadh

Answered by abhijita6lm
0

Answer:

NADH+H+ is re-oxidized to NAD+ during the process of fermentation.

Explanation:

NAD+ is reduced to NADH and H+ during many processes such as glycolysis and the Krebs cycle. During glycolysis, two molecules of NAD+ are reduced to produce two molecules of NADH. During the Krebs cycle, three molecules of NAD+ are reduced to produce three molecules of NADH.

The produced NADH has to be recycled back in order to stimulate the occurrence of other processes. Thus, the NADH produced is re-oxidized to its initial form of NAD+ through a process called fermentation. During the process of fermentation, there is a conversion of pyruvic acid into lactic acid and ethanol. This conversion is coupled by the re-oxidation process of NADH and H+ to NAD+.

So, the answer is fermentation.

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