Question

The reduction electrode potential E, of 0.1 M solution
of M* ions (E = -2.36 V) is :​

Answer 1

Answer:

what is the meaning of this question

Answer 2

Answer:

The reduction electrode potential E of 0.1 M solution is -2.41 V

Explanation:

Number of electrons = 1 (for single electrode potential)

[M⁺] = 0.1 M

E° = -2.36V

Using Nernst Equation

$\boxed{E=E^0+\frac{0.059}{n}\log[M^+]}$

$\implies E=-2.36+\frac{0.059}{1}\log0.1$

$\implies E=-2.36-0.059=-2.419$

Thus the reduction electrode potential E of 0.1 M solution is -2.41 V

Hope this is helpful to you.