The reflection of the point (4, -13) about the line 5x + y + 6 = 0 is
(-1 , -14)
(1,2)
(3,4)
(0,0)
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Let the image of (2,4)=(h,k) Then
ah−x1=bk−y1=a2+b2−2(ax1+by1+c)
⇒1h−2=1k−4=12+12−2(2+4−10)
⇒h−2=+4 ∣k−4=4
h=6∣k=8
∴(h,k)=(6,8)
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