Physics, asked by elviinsingh6191, 10 months ago

The refracted index of water is 1.33 calculate it's critical angle

Answers

Answered by Anonymous
27

 \bold{ \large{  \underline{ \underline{ \: Answer : \:  \:  \: }}}}

 \to Critical angle = 48.590 Degrees

 \large \bold{ \underline{ \underline{ \: Explanation \:  : \: \:  \:  }}}

  \to Refractive index = 1.33

The Relation between Critical Angle (C) and Refractive index (R.I) is :

 \large \bold{ \fbox{ \fbox{R.I =  \frac{ \: 1 \:  \: } { \:  \: sin  \: C \:  \: }    }}}

 \to 1.33 = 1 / sin C

 \to sin C = 0.75

 \to C = 48.590 Degrees

 \therefore Critical angle is 48.590 Degrees

Answered by behdhdjwkwoi3nrnd
2

Answer:

The refracted index of water is 1.33 calculate it's critical angle

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