Question

There is a 5digit no. 3 pairs of sum is eleven each. Last digit is 3 times the first one. 3 rd digit is 3 less than the second.4 th digit is 4 more than the second one. Find the digit.

Answer 1

Answer:

The statement that "3 pairs of sum is eleven each is ambiguous.  cannot solve this. Explanation is given below.

Step-by-step explanation:

The number = a b c d e.

e = 3 a.   SInce the digits are between 0 and 9, and a is not equal to 0,

e is not equal to 0.

So   a = 1, 2 or 3.... and e = 3, 6 or 9.

So   (a, e) = (1, 3) or (2, 6) or (3, 9).

Given also

c = b - 3.  or,  b = c + 3.

and,  d = b + 4.

So  b can be 3, 4 , or 5 only.

and Hence, c can be 0, 1, or 2 only.

Hence d can be 7, 8 or 9 only.

So (b, c, d) =  (3, 0, 7) or (4, 1, 8) or (5, 2, 9).

 

Do not understand this statement that "3 pairs of sum is eleven each." ??

It is not making a good sense.

Answer 2

Step-by-step explanation:

Let the require number be d1d2d3d4d5

Given d5=3d1

d3=d2-3

d4=d2+4

since sum of pair of digits=11

consider d3+d4=11

d2-3+d2+4=11

=> d2=5

d3=d2-3

d3=5-3

d3=2

d4=d2+4=5+4

d4=9

hence require number = __529__

here 9+2=11

now we have think of a number which should be added to five to get 11

5+6=11

hence the last number is 6

since d5=3d1

∴d1=2

hence the ans is 25296

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