Question

The refractive index of a medium is found to vary with wavelength as refractive index= a+b/ λ2. what are the dimensions of a and b

Answer 1

Refractive index has no dimension.
Thus if a + (b/lambda ²) = refractive index.
Thn, a had no dimension and b has dimension of [ L²].
Hope I helped you.

Answer 2

Answer:

A is dimensionless.

Dimension of B/ λ^2 =>

                      [B] / [L^2] = [M^0L^0T^0]

                                 [B] = [M^0L^2T^0]

Or,                  [B] = [L^2]

Hope you found that Helpful !