Question

The refractive index of a medium of dielectric constant 2 and relative permeability 1.28 is

Answer 1

Answer:

Loght is an electromagnetic wave, and Maxwell showed that light [math]c[/math] travels at the EM velocity [math]U/\sqrt{\epsilon\mu}[/math]. SI sets U=1, but in CGS, U is a derived constant with units etc, because [math]\epsilon[/math] and [math]\mu[/math] are both set to unity. It is the comparison between the values of c and U that set the electromagnetic theory of light in motion.

Answer 2

Given:

• Dielectric constant $( \epsilon_r) = 2$
• Relative permeability $( \mu_r) = 1.28$

To Find:

• Refractive index $(n)$ of the medium

Solution:

Relation between refractive index, relative permittivity and the relative permeability is given by

               $n= \sqrt{\mu_r \epsilon_r}$

Putting the value of all these

we get,

            $n =\sqrt{2 \times 1.28}$

           $n = \sqrt{2.56} \\n = 1.6$

Thus, Refractive index $(n)$ of the medium is $1.6$