Physics, asked by Prema111, 1 year ago

The refractive index of dense flint glass is 1.65 and for alcohol, it is 1.36 with respect to air the refractive index of the dense flint glass with respect to alcohol is.

Answers

Answered by pavaniraju
152


The refractive index of dense flint glass with respect to air is

n21 = n2/ n1 = n2 =1.65 (because n1 = 1.00)

The refractive index of alcohol, with respect to air,

n31 = n3/ n1 = n3 =1.36 (because n1 = 1.00)

The refractive index of flint glass, with respect to alcohol is,

n23 = n2/ n3 = 1.65/1.36 = 1.21

Thus, the refractive index of dense flint glass with respect to alcohol is 1.21


hope so it helps..
Answered by AnkitaSahni
6

Given:

The refractive index of dense flint glass with respect to air is 1.65

The refractive index of alcohol with respect to air is 1.36

To Find:

The refractive index of dense flint glass with respect to alcohol.

Solution:

What is the refractive index?

  • The Refractive index of a medium is the ratio of the speed of light in a vacuum and the speed of light in the given medium.

Mathematically,

                                 μ = \frac{c}{v}                                  (1)

where c is the speed of light in a vacuum (3 × 10^{8} m/s)

    and v is the speed of light in the medium

To find the refractive index of dense flint glass with respect to alcohol, we will follow these steps:

1. Express the refractive indices of flint glass and alcohol.

  • Refractive index of dense flint glass w.r.t to air :

                           μₐ¹ = \frac{mu of flint}{mu of air} = 1.65                            (2)

  • Refractive index of alcohol w.r.t to air:

                         μₐ² = \frac{mu of alcohol}{mu of air} = 1.36                          (3)

2. Find the refractive index of flint glass w.r.t to alcohol.

  • The refractive index of flint glass w.r.t to alcohol can be given as:

                         μ¹₂ = \frac{mu of flint glass}{mu of alcohol}

  • We can get this expression by dividing (2) by (3):

                             μ¹₂ = \frac{mu of flint glass}{mu of air} × \frac{mu of air}{mu of alcohol}     (taking reciprocal of 3)

                           ⇒μ¹₂ = \frac{1.65}{1.36}                                       (from 2 and 3)

                          ⇒ μ¹₂ = 1.21

Thus the refractive index of dense flint glass with respect to alcohol is 1.21.

       

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