Question

the refractive index of water in an experiment was observed to be 1.30, 1.34, 1.35, 1.32 , 1.36, 1.33 . calculate relative % error . express the final result in % error. ​

Answer 1

Answer:

Explanation:

1.30+1.34+1.35+1.32+1.36+1.33/6

= 1.33

absolute error = 0.03+0.01+0.02+0.01+0.03+0.00/6

= 0.1

relative error= 0.1/1.33

= 0.075

% error = 0.075*100

= 7.5%