Question

Yellow light emitted from a sodium
lamp has a wavelength (2) of 580 nm.
Calculate the frequency (v) and
wavenumber (ū) of the yellow light.​

Answer 1

Answer:

Wavelength = 580 nm

C= Wavelength × Frequency = 3×10^8 m/s

Frequency = C/Wavelength = 3×10^8/580×10^-9 s^-1

= 3×10^8/58×10^-8 s^-1

=0.0517241379 × 10^16 s^-1

= 517,241,379 × 10^6 s^-1

Wave Number = 1/ Wavelength

= 1/ 580 ×10^-9 m^-1

=1/58 × 10^-8 m^-1

=0.0172413793 × 10^8 m^-1

Answer 2

Answer:

frequency= $5.17*10^{14}$ $s^{-1}$

wavenumber= $1.742*10^{6}$ $m^{-1}$

Explanation:

wavelength of sodium lamp(λ)=580nm=$580*10^{-9} m^}$

as we know the equation, c = λf

and the velocity of light(c) =$3*10^{8}$ m/s

frequency(f)=c/λ

f=($3*10^{8}$)/580= $5.17*10^{14}$ $s^{-1}$

and wavenumber is nothing but the reciprocal of λ

wavenumber =1/λ = $1.742*10^{6}$ $m^{-1}$