Question

The refractive index of water is 1.33 and kerosene is 1.44. calculate the refractive index of kerosene with respect to water

Answer 1

$\text{refractive index of water } = \bold{1.33}$
$\text{refractive index of kerosene } = \bold{1.44}$
$\text{refractive index of kerosene with respect to water } = \frac{\mu_k}{\mu_w}$
Where , $\mu_k$ is refractive index of kerosene
And $\mu_w$ is refractive index of water

Now, $^k\mu_w= \text{refractive index of kerosene with respect to water } =\frac{1.44}{1.33}$
= 1.082

Answer 2

n kw ( refractive index of kerosene w.r.t. water) is equal to :
nk/nw ( refractive index of kerosene /refractive index of water)

>> nkw = nk/nw

=1.44/1.33
= 0.182*

this is ur required answer
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