Physics, asked by vivekdwivedy5, 9 months ago

the refractive index of water is 4/3 and speed of light in air is 3×10^8.find speed of light in the water.​

Answers

Answered by SarcasticL0ve
37

GivEn:

  • refractive index of water is \sf \dfrac{4}{3}

  • Speed of light in air is 3 × \sf 10^8

To find:

  • Speed of light in the water.

SoluTion:

Refractive Index is the measure of bending of light when it passes from one medium to another medium.

It is the ratio of speed of light (c) in empty space or a vaccum to speed of light (v) in medium.

:\implies\sf \purple{Refractive\;index = \dfrac{Speed\;of\;light\;in\;air}{Speed\;of\;light\;in\;medium}}\\\\ :\implies\sf n = \dfrac{c}{v}\\\\ {\underline{\bf{\bigstar\;Now,\; According\;to\; Question\;:}}}\\\\ \;\;\;\bullet\;\;\sf refractive\; index\; of \;water \;is\; \dfrac{4}{3}\\\\ \;\;\;\bullet\;\;\sf Speed\; of \;light\; in \;air \;is\; 3 \times 10^8

\rule{170}2

Here,

★ Given Medium (v) is water.

\maltese\;{\boxed{\sf{\pink{Refractive\;index = \dfrac{Speed\;of\;light\;in\;air}{Speed\;of\;light\;in\;water}}}}}\\\\ \dashrightarrow\sf \dfrac{4}{3} = \dfrac{3 \times 10^8}{v}\\\\ \dashrightarrow\sf v = 3 \times 10^8 \times \dfrac{3}{4}\\\\ \dashrightarrow{\underline{\boxed{\sf{\purple{v = 2.25 \times 10^8\;m/s}}}}}\;\bigstar\\\\ \therefore\;\sf \underline{Speed\;of\;light\;in\;water\;is\; \bf{2.25 \times 10^8\;m/s}}.

Answered by Anonymous
1

Given ,

The refractive index of water is 4/3

We know that ,

The refractive index of medium is defined as the ratio of speed of light in vacuum to the speed of light in medium

It is denoted by " n "

Mathematically ,

 \boxed{ \tt{n =  \frac{c}{v} }}

Thus ,

 \mapsto \tt v =  \frac{3 \times3  \times  {(10)}^{8} }{4}

 \mapsto \tt v =  \frac{9 \times  {(10)}^{8} }{4}

 \mapsto \tt v = 2.25 \times  {(10)}^{8}  \:  \: m/s

The speed of light in the water is 2.25 × 10^(8) m/s

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