Question

the refractive index of water with respect to air is 1.33. the velocity of light in vacuum is 3×10 power 8 m/s. calculate the velocity of light in water.

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\large\red{\boxed{\sf Velocity\:(v)=2.2×10^8m/s}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Refractive index of water with respect to air $\sf{(_g\mu_w)=1.33}$

• Velocity of light in vacum (c)=$\sf{3×10^8m/s}$

$\large\underline\pink{\sf To\:Find: }$

• Velocity of light in water (v)=?

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We know that ,

Refractive index is ratio of two velocities. Velocity of air and Velocity of medium .

$\large{\boxed{\sf _g\mu_w=\frac{c}{v} }}$

$\large\implies{\sf 1.33=\frac{3×10^8}{v} }$

$\large\implies{\sf v=\frac{3×10^8}{1.33} }$

$\large\implies{\sf v=2.2×10^8m/s}$

$\large\red{\boxed{\sf Velocity\:(v)=2.2×10^8m/s}}$

Hence ,

Velocity of light in water is $\sf{2.2×10^8m/s}$

Answer 2

$\huge{\bold{\underline{\underline{Answer:-}}}}$

$\large\pink{\boxed{\sf Velocity \: of \:light=2.2 \times\ 10^8m/s }}$

${\bold{\underline{\underline{Given:-}}}}$

•Refractive index of water in respect to air $\ (_u g_w)\to\ 1.33$

•Velocity of light in Vaccum $\to\ 3 \times\ 10^8m/s$

${\bold{\underline{\underline{To \: find :-}}}}$

• Velocity of air in water $\to\ ?$

${\bold{\underline{\underline{Step-by-step- Solution:-}}}}$

we know that ;

$\large\bf\ _g u_w = \frac {Velocity \: in \: vaccum}{Velocity \: to \: water}$

$\large\sf\to\ 1.33 =\frac {3 \times\ 10^8}{v} \\ \\ \large\sf\to\ v =\frac {3 \times\ 10^8}{1.33} \\ \\ \large\bf\to\ v=2.2 \times\ 10^8m/s$

;)