Question

the Refrective index of the material of a Prism is √3/2and the angle of the Prism is 90° Find the angle of minimum deviation and corresponding angle of incidence.​

Answer 1

The angle of minimum deviation is 30°.

Answer 2

Answer:

Let μ=

2

3

be the refractive index of prism.

Refracting angle of prism isA=90

°

At minimum deviation ,angle of incidence =angle of emergent

Therefore, 1×sinI=μ×sinr

1

1×sine=μ×sinr

2

Since, I=e

Therefore, r

1

=r

2

A+90

°

−r

1

+90

°

−r

2

=180

°

Therefore, r

1

=45

°

1×sinI=μ×sin45

°

Therefore, I=60

°

minimum deviation=2×i−90

minimum deviation=30

°

Hence, Option c is answer

Explanation:

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