Physics, asked by Rinisha08, 1 year ago

The relation 3t = √3x + 6 describes the displacement of a particle in one direction where x is in metres and t in seconds. The displacement, when velocity is zero is

Answers

Answered by smartAbhishek11
33
ι нσρє уσυ нєℓρ !!!
==================
тнєяє ιѕ αиѕωєя вєℓσω !!
========================

Given relation can be written as
3t-6 = (3x)1/2
 squaring both side and solve we get
3x= 9t2+36-36t……………………………(1)
diffrentiate both side wrt time
differenciation of position will give instantanious velocity
hence 3v= 18t -36-0
at t=2 second v=0
put t=2 in equation.............(1)
3x= 36+36-72
x= 0

but at t=0 x=12
so diplacement = 0-12= -12 m

Rinisha08: Thank you! :)
Rinisha08: 11th.
Rinisha08: I didn't get the last two steps. at the t = 0 x = 12?
Rinisha08: Got it. But how did ya calculate displacement
Rinisha08: Final - initial ?
Rinisha08: At the = 0 velocity should be zero
Answered by Anonymous286
28
Now About the last 2 steps
Displacement is actually change in position
So understand this
Here Ur intial position is 12 which is actually origin for u since u start from that position
Now assume u being standing intially at that position
Now u walk towards the negative side that is on the left side
So now u stop at zero
So Ur final position is 0
So net displacement=Final position-intial position
=0-12
=-12
which actually means u took 12 steps towards Ur left
so the answer -12
Hope u understand
Hope it helps
:)
(Mention doubts in comments if u want)
Attachments:

Rinisha08: i tried doing that ;P
Rinisha08: anyways insta handle - @rinisha_pillai
Anonymous286: ok
Anonymous286: actually then i can't inbox
Anonymous286: we need to have already 1000 answers
Rinisha08: hmm
Rinisha08: u could hv dm'd me.
Rinisha08: just saying cz I'm not keeping this acc anymore.
Anonymous286: acha ok
Anonymous286: but why?
Similar questions