The relation between the acceleration and time for an object is below. Calculate velocity with which object is moving at t=1 s (At t=0, v=0) a= 3t-4t^2
Answers
Answered by
142
a = 3t - 4t^2
dv/dt = 3t - 4t^2
dv = (3t - 4t^2)dt
Integrate
v = 3t^2/2 - 4t^3/3
At t = 1s
v = 3/2 - 4/3
v = 0.166m/s
It’s velocity at t = 1s is 0.166m/s
dv/dt = 3t - 4t^2
dv = (3t - 4t^2)dt
Integrate
v = 3t^2/2 - 4t^3/3
At t = 1s
v = 3/2 - 4/3
v = 0.166m/s
It’s velocity at t = 1s is 0.166m/s
Answered by
2
Answer:
0.16m/s.
Explanation:
A = 3t - 4t2dv/dt = 3t - 4t2
dv = (3t - 4t2)dt
Integrate
v = 3t2/2 - 4t3/3
At t = 1s
v = 3/2 - 4/3
v = 0.166m/s
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