The relation between the time t and position x for a particle moving on x axis
Answers
Answered by
0
Answer:
Explanation:
note: dx/dt = v dv/dx=a and (dv/dx)*(dx/dt)=a
t=px2+qx
on differentiating wrt t , we have
1=2pxv+qv .....(1)
on differentiating wrt x , we have
0=2pv+2px.dv/dx +q.dv/dx
0=2pv+2px.(a/v) +q.(a/v)
0=2pv2+2pxa +qa ....(2)
from (1) and (2) ..we have
2pv3+a=0
hope it will help you
Similar questions