The relation between the two systems of measurement of temperature Kelvin and Fahrenheit is given by the linear equation F = 9 5 ( − 273) + 32 i) Find the temperature of the liquid in Fahrenheit if the temperature of the liquid is 3130K. ii) If the temperature is 1580F , then find the temperature in Kelvin.
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Relationship between Kelvin and Fahrenheit is
y=9/5(x-273)+32...(1)
i)
Given that, x = 313K
From (i), we get
y = 9/5 * (313 - 273) + 32
= 9/5 (40) + 32
= (9 × 8) + 32 X
= 72 +32
= 104
Therefore, the temperature of the liquid
in
Fahrenheit scale be
ii)
Given that, y = 158° F
From (1), we get
158 = 9/5 * (x - 273) + 32
or, 9/5 * (x - 273) = 158 - 32
or, 9/5 * (x - 273) = 126
or, x-273 = 5/9 (126)
or, x - 273 = (5 * 14)
or, x = 70 + 273
or, x = 343
Therefore, the temperature of the liquid in
Kelvin scale be 343 K
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