Question

The relative atomic mass of chlorine is 35,5.Calculate the percentage of Cl-35in natural chlorine

Answer 1

The relative atomic mass of chlorine is 35.5

Therefore, 35.5=Cl37.x+Cl35.(100-x)/100

[x=percentage of Cl37 in atmosphere]

=3550=37x+3500-35x

=2x+3500

3550-3500=2x

2x=50

x=25

Therefore percentage of Cl 37 is 25% and Cl 35 is 75%