The relative atomic mass oF iridium is 192.22. Explain whether a naturally occurring sample of iridium contains more 191 Ir or 193 Ir.
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Answer:
191x + 193(1-x) = 192.23
x = .385
so,
38.5% Ir191
61.5% Ir193
or, since 192.23 is about 5/8 of the way from 191 to 193, 5/8 will be Ir193, or 62.5%.
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