Question

The relative density of 7.8 what is its density

Answer 1

Answer:

RD=

densityofwater

densityofiron

RD=

10

3

kgm

−3

7.8×10

3

kgm

−3

⇒RD=7.

Answer 2

Answer:

$rd = \frac{density \: of \: iron}{density \: of \: water}$

$rd = \frac{7.8 \times 10 ^{3} kgm {}^{ - 3} }{ {10}^{3} kgm {}^{ - 3} }$

$rd = 7.8$