Question

The relative molecular mass of Na2SO3.5H2O is *

A.250 amu

B. 250g

C.248 amu

D.249​

Answer 1

Answer:

250 amu iss the answer

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Answer 2

Given:

The compound is $Na_2SO_3.5H_2O$.

To find:

The relative molecular mass.

Solution:

The compound is $Na_2SO_3.5H_2O$.

The atomic mass of Na is 23 amu and the Sulfur atom is 32 amu.

The atomic mass of the H atom is 1 amu and the atomic mass of the oxygen atom is 16 amu.

This compound has two Na atoms, one S atom, three oxygen atoms and five water molecules.

Hence the relative molecular mass is as follows-

$23 \times 2 + 32 + 3 \times 16 + 5 \times (2 \times 1 + 16) \\ = 46 + 32 + 48 + 90 \\ = 216$

The relative molecular mass of $Na_2SO_3.5H_2O$ is 216 amu.