Question

The relative rate of diffusion of a gas (Mol wt. = 98)
as compared to hydrogen will be :
(1) 1/7
(2) 1/5
(3) 1/4
(4) 1​

Answer 1

Answer:

1 /7

Explanation:

relative gas=root under molwt of h2/molwt of gas

=root under 2/98

=1/7

Answer 2

The relative rate of effusion of gas X to hydrogen gas is $\frac{1}{7}$

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

So,

$\frac{\text{Rate}_X}{\text{Rate}_{H_2}}=\sqrt{\frac{M_{H_2}}{M_{X}}}$

We are given:

Molar mass of hydrogen gas = 2 g/mol

Molar mass of X gas = 98 g/mol

Putting values in above equation, we get:

$\frac{\text{Rate}_X}{\text{Rate}_{H_2}}=\sqrt{\frac{2}{98}}\\\\\frac{\text{Rate}_X}{\text{Rate}_{H_2}}=\sqrt{\frac{1}{49}}\\\\\frac{\text{Rate}_X}{\text{Rate}_{H_2}}=\frac{1}{7}$

Learn more about Graham's law:

https://brainly.com/question/13255462

https://brainly.com/question/11288718

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