Question

The remainder is 47 when a number is divided by 779. What is the remainder when this numbe
divided by 19 ?
in wanho p ) are given below for some polynomial pex). Find the aber​

Answer 1

Answer:

remainder is 9

Step-by-step explanation:

Number = ( 779 x a) + 47, where "a" is the quotient

= (19 x 41 x a) + (19 x 2) + 9

= 19 x (41a + 2) + 9

= 19 x (New quotient) + 9

therefore Required remainder = 9

i m not sure plz tell me the write ans if i am wrong