Question

The remainder obtained when (4x^3)–(3x^2)+(2x)+(1) is divided by x+1​

Answer 1

Answer: This is your answer

Answer 2

Step-by-step explanation:

Given expressions is

$(4{x}^{3}-3{x}^{2}+2x+1) \div x+1$

$= \frac{4 {x}^{3} - 3 {x}^{2} + 2x + 9 - 8} {x + 1}$

$= \frac{4 {x}^{3 } + 4 {x}^{2} - 7 {x}^{2} - 7x + 9x + 9 - 8 }{x + 1}$

$= \frac{4 {x}^{2}(x + 1) - 7x(x + 1) + 9(x + 1) - 8}{x + 1}$

$= \frac{(x + 1)(4 {x}^{2} - 7x + 9) - 8 }{x + 1}$

$= \frac{(x + 1)(4 {x }^{2} - 7x + 9) }{x + 1} + \frac{ (- 8)}{x + 1}$

Therefore,

Quotient = 4x2-7x +9 and

Remainder = (-8)