Question

the remainder of x³-6x²+2x-4 divided by 3x-1 by long division method? ​

Answer 1

Answer:

let g(x)= 0

3x-1=0

x=1/3

Step-by-step explanation:

Now put value of x in p(x)

p(1/3)= (1/3)^3 -6(1/3)^2+2(1/3)-4

=1/27-6(1/9)+2/3-4

=1/27-2/3+2/3-4

=1/27-4

=1-128/27

=-127/27