Question

The remainder , when (1523+2323) is divided by 19, is
A.4
B.15
C.0
D.18

Answer 1

ANSWER:-
Use the formula: Remainder(A^n + B^n/ A+B )=0 When n=odd.

Here Remainder (15^23+23^23/ 19).

N is odd.

so , 15+23= 38.

and 38 is divisible by 19

PLEASE MARK AS BRAINLIEST

Answer 2

hey mate !!❤✌
here's ur answer ⤵⤵⤵



Formula: Remainder(A^n + B^n/ A+B )=0 When n=odd

Here Rem(15^23+23^23/ 19)

N is odd

so , 15+23= 38

and 38 is divisible by 19

so Remainder :- 0

⭐ hope it helps ⭐