Math, asked by ghanishydhas, 11 months ago

The remainder, when a^9- b^9 is divided by a² + ab + b² is
a) a-b
b) a+b
c) 1
d) 0​

Answers

Answered by quaalex3
2

Answer:

remainder is 0

Factor a⁹-b⁹= (a³)³-(b³)³=(a³-b³)(a⁶+b⁶+a³b³)

=(a-b)(a²+ab+b²)(a⁶+b⁶+a³b³)

now whwn you divide by given divisor it cancels out with the factor in a⁹-b⁹

Hope this helps you.☺️

Answered by channelspk83
0

Answer:

d)0

Step-by-step explanation:

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