The remainder, when a^9- b^9 is divided by a² + ab + b² is
a) a-b
b) a+b
c) 1
d) 0
Answers
Answered by
2
Answer:
remainder is 0
Factor a⁹-b⁹= (a³)³-(b³)³=(a³-b³)(a⁶+b⁶+a³b³)
=(a-b)(a²+ab+b²)(a⁶+b⁶+a³b³)
now whwn you divide by given divisor it cancels out with the factor in a⁹-b⁹
Hope this helps you.☺️
Answered by
0
Answer:
d)0
Step-by-step explanation:
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