Question

the remainder when p(x)=2xsquare-x-6 is divided by (x-2) is​

Answer 1

I ope this is helpful. keep learning

Answer 2

Step-by-step explanation:

$2 {x}^{2} - x - 6$

x - 2 = 0

x = 2

by trial method

Now put value of x we get remainder.

$-- > 2 \times {2}^{2} - 2 - 6$

$-> 2 \times 4 - 2 - 6$

$- > 8 - 8$

$- > 0$