The repulsive force between two magnetic poles in air is 16×10‐³N.if a two poles are equal in strength and are seperated by a distance of 20 cm , calculate the pole strength of each pole
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Answer:m
1
=40 Am,m
2
=10 Am,d
1
=20 cm
d
2
=10cm
F=
4πd
2
μm
1
m
2
F
1
=
(20×10
−2
)
2
10
−7
×40×10
=10
−3
Force is inversely proportional to d
2
F
2
=4×10
−3
m
1
=40 Am,m
2
=10 Am,d
1
=20 cm
d
2
=10cm
F=
4πd
2
μm
1
m
2
F
1
=
(20×10
−2
)
2
10
−7
×40×10
=10
−3
Force is inversely proportional to d
2
F
2
=4×10
−3
Explanation: you would need to times your number to the nearest tens to get your -3
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