The required solution of quadratic equation y^2 - 8y + 16 = 0 is :
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Answered by
1
Answer:
y²-8y+16 = 0
= y²-4y-4y+16 = 0
= y(y-4)-4(y-4) = 0
= (y-4)(y-4) = 0
solutions
=> y-4 = 0
=> y = 4
Hence,the required solution of quadratic equation y^2 - 8y + 16 = 0 is 4
i hope this answer helps you.
Answered by
0
Answer:
I hope this helps you
Step-by-step explanation:
y2 - 8y + 16 = 0
y2 - 4y - 4y + 16 = 0
y(y-4) -4 (y-4) = 0
(y-4) (y-4) = 0
y = 4 or y = 4.
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