Math, asked by manjinder14samplay, 3 months ago

The required solution of quadratic equation y^2 - 8y + 16 = 0 is :​

Answers

Answered by ajsheetal
1

Answer:

y²-8y+16 = 0

= y²-4y-4y+16 = 0

= y(y-4)-4(y-4) = 0

= (y-4)(y-4) = 0

solutions

=> y-4 = 0

=> y = 4

Hence,the required solution of quadratic equation y^2 - 8y + 16 = 0 is 4

i hope this answer helps you.

Answered by Archita88
0

Answer:

I hope this helps you

Step-by-step explanation:

y2 - 8y + 16 = 0

y2 - 4y - 4y + 16 = 0

y(y-4) -4 (y-4) = 0

(y-4) (y-4) = 0

y = 4 or y = 4.

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