Question

The resistance between any two terminals of a balanced star connected load is 12 ohms the resistance of the each phase is..?

Answer 1

18 ohm is the answer

Answer 2

Answer:

Explanation:

The resistance between any two terminals of a balanced star connected load is $12 ohms$ .

To get the resistance of each phase, we will use this formula:

$R_{a b}=R_{a}+R_{b}$  for $a$ and $b$ phase .

Similarly we can write : $R_{b c}=R_{b}+R_{c}=12$ for $b$ and $c$ phase.

And $R_{c a}=R_{c}+R_{a}=12$ for $c$ and $a$ phase.

Add this three equation to know the resistance of each phase.

$R_{a b}+R_{b c}+R_{a c} = 2\left(R_{a}+R_{b}+R_{c}\right)=12 \times 3$ .

Therefore , $R_{a b}+R_{b c}+R_{a c}=\frac{12 \times 3}{2} =18$ .

As it is mentioned that these are balanced star network , then

$R_{a}=R_{b}=R_{c}=R$

So, $3R=18$

And the value of $R$ is $\frac{18}{3} =6$

The resistance of eac phase is $6 ohms$ .

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