Question

The resistance is 6ohm is connected in series with another resistance 4ohm. a potential difference of 20v is applied across the combination. calculate the current through circuit & potential difference across its circuit

Answer 1

Aɴꜱᴡᴇʀ

☞ Voltage across the circuit = 20 V

☞ Current = 2 A

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Gɪᴠᴇɴ

➳ Two resistors each of 6 $\sf\Omega$ and 4 $\sf\Omega$ are connected in series

➳ Potential difference (V) = 20 volts

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Tᴏ ꜰɪɴᴅ

✭ Potential difference?

✭ Current through the circuit?

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Sᴛᴇᴘꜱ

❍ To find the answer w first have to find the net resistance which is given by(for series)

$\large \underline{ \boxed{ \sf{R_{net} = R_1 + R_2............R_n}}}$

So substituting the given values,

$\large \sf\leadsto{}R_{net} = 6 \Omega + 4 \Omega \\ \\ \large \sf \leadsto \green{R_{net} = 10 \Omega}$

So now we can find th current (I) in the circuit with the help of the Ohm's law, that is V = IR

$\large \dashrightarrow{} \sf{}V=IR \\ \\ \large \sf \dashrightarrow{} I = \frac{V}{R} \\ \\ \large \sf \dashrightarrow{}I = \cancel\frac{20}{10} \\ \\ \large \sf{} \pink{\dashrightarrow{}I = 2 \: A}$

❍ And the potential difference across the circuit is always the same in any point of the circuit and so its given in the question itself as 20 V

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Answer 2

Answer:

Given:

let the resistance be R and R' .

R = 6 ohm

R' = 4ohm

potential difference = 20v

Equivalent resistance = R + R'

= 6 + 4 = 10 ohm

To Find :

• Potential difference
• Electric current

Solution :

By Ohm's law :

V=I*R

by subtituting the values-

Let I(electric current ) be - x

$20 = x\: \times 10 \\ x = \frac{20}{10} \\ x = 2$

Electric current = 2 Ampere

and potential difference be the same ,that is,20v