Question

the resistance of 0.01 M NaCl in a conductivity cell is 210 ohms the molar conductance of this solution is 4.5 *10^3 Scm2 mol^-1 calculate cell constant of the conductivity cell​

Answer 1

Answer:

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Answer 2

Cell constant of the conductivity cell is found to be 9.45.

Concept:

Conductivity cells or conductivity electrodes also called as probes which are constructed from metal electrodes placed at a fixed distance in a container made-up of glass or plastic body.

The ratio of the distance between the electrodes to their surface area is termed as cell constant.

Formula:

∧m =k×1000 / m

∧m= molar conductance

k= Kappa

m= molar concentration

Given,

∧m= 4.5 *10^3 Scm2 mol^-1

m= 0.01M

R= resistance= 210 ohms

Calculation:

4.5 × 10^3 =k ×1000/ 0.01

so, k= 0.045

Calculation for cell constant:

k= cell constant/ resistance

0.045 = cell constant/ 210

Therefore, Cell constant= 0.045 × 210 = 9.45 .

Hence, Cell constant of the conductivity cell is found to be 9.45.

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