The resistance of a coil is 4.2 at 100oc and the temperature coefficient of resistance of its material is 0.004oc. Its resistance will be 4 at
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The resistance of a coil is 4.2 Ω at 100°C and the temperature coefficient of resistance of its material is 0.004/°C.
To find : the temperature at which resistance of coil will be 4 Ω.
solution : using formula, R = R₀[1 + α∆T]
here at temperature = T, R₀ = 4
and resistance, R = 4.2 at temperature = 100°C
so, 4.2 = 4[1 + 0.004/°C × (100°C - T)]
⇒4.2 = 4 + 4 × 0.004 × (100 - T)
⇒0.2 = 0.016 × (100 - T)
⇒0.2/0.016 = 100 - T
⇒12.5 = 100 - T
⇒T = 87.5 °C
Therefore the temperature is 87.5°C at which resistance of the coil will be 4 Ω
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Answer:
4
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