The resistance of a conductivity cell containing 0.001 M KCl solution at 298K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298K is 0.146 X 10 -3 S/ cm.
Answers
Answer:
pasteurization or pasteurisation is a process in which water and certain packaged and non-packaged foods (such as milk and fruit juice) are treated with mild heat, usually to less than 100 °c (212 °f), to eliminate pathogens and extend shelf life. the process is intended to destroy or deactivate organisms and enzymes that contribute to spoilage or risk of disease, including vegetative bacteria, but not bacterial spores.[1][2] since pasteurization is not sterilization, and does not kill spores, a second "double" pasteurization will extend the quality by killing spores that have germinated.
the process was named after the french scientist louis pasteur, whose research in the 1880s demonstrated that thermal processing would inactivate unwanted microorganisms in wine.[2][3] spoilage enzymes are also inactivated during pasteurization. today, pasteurization is used widely in the dairy industry and other food processing industries to achieve food preservation and food safety.
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Answer:
0.219
Explanation:
because cell constant=K÷G=L÷A
but 1÷G=Resistance
so cell constant= K×1÷G = K×Resistance= 0.146×10-^3× 1500= 0.219