The resistance of a conductivity cell containing 0.001M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001M KCl solution at 298 K is 0.146 × 10−3 S cm−1.
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Answer:
0.219 cm−1
Explanation:
Conductivity of the cell = K = 0.146 × 10−3 S cm−1 (Given)
Resistance of the cell , R = 1500 Ω (Given)
Conductivity of solution = 0.001M KCl (Given)
According to the formula of cell constant -
Cell constant = κ × R
Substituting the values we will get -
= 0.146 × 10−3 × 1500
= 0.219
Therefore, the cell constant if conductivity of 0.001M KCl is 0.219 cm−1
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see the attachment okay
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