Question

The resistance of a galvenometer is
100 ohm and maximum current which
can pass through 0.001 A.
The
value of
shunt to change
galvanometer into voltmeter of 12 volt range will be :
1. 12100 ohm
2. 11900 ohm
3. 1190 ohm
4. 11990 ohm
​

Answer 1

Answer:

2) 11900Ω

Explanation:

Given : $R_g=100$ Ω

            $I_g=0.001A$

            Required voltage ($V_g$) = 12V

Let the shunt resistance be $R_s$ Ω

Now the resistance of voltmeter is $R=R_g+R_s$ because, they are connected in series

$\therefore (R_g+R_s)I_g=V_g\\\\=>(100+R_s)=12000\\\\=>\boxed{R_s=11900}$

Hope this answer helped you :)