the resistance of a wire is 10 ampere. its length is increased by 10 percent by stretching. the new resistance will now be?
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R=2x+(x^2/100). x=10%
R = 20+100/100
=21%
so new resistance will be R+21R/100
R = 20+100/100
=21%
so new resistance will be R+21R/100
ishitapathuri:
thank you....but the answer is 12 ampere......i just require the process sista
yes if you put R=10 then you will get approx 12
Do you need proof of formula
not required
tnx
ok :)
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