The resistance of a wire is 4 ohm. Calculate its new resistance if the radius of the wire is one-third of the original wire
please someone answer this question
Answers
The resistance of a wire is 4 ohm. Calculate its new resistance if the radius of the wire is one-third of the original wire ?
✏ The new resistance of wire is 12 Ω .
Given :-
- The resistance of a wire is 4 ohm.
- The radius of the wire is one-third of the original wire.
To Find :-
- The new resistance of wire.
Theory Involved :-
Resistance of a conductor is the property by virtue of which it opposes the charge through it.
R =
S.I. unit of resistance :- 1 Ω = 1 VA-¹
The resistance of conductor is directly proportional to its length;
R ∝ l .......... (1)
The resistance of conductor is inversely proportional to its area of cross section ;
R ∝ ........... (2)
From 1 & 2 ,
R = p
______________________________________
Calculation :-
According to the question,
The resistance of wire = 4 Ω
Let the area be r;
So, The Area of cross-section = r
Using resistivity Formula;
R = p
➡ 4 = p
➡ 4 r = p I
➡ I = 4r/p
Now,
The radius of the wire is one-third of the original wire. So, new resistance
When R = 1/3 r,
=> R = p. l/a
=> R = p . 4r/a
=> R = p . 4r/pa
=> R = 4r/a
We know,
Area a = r/3
=> R = 4r/r/3
=> R = 4× 3
=> R = 12
➡ R = 12 Ω
_______________________________________
Answer:
Explanation:
Resistance= (pl)/a
l=length of wire
a=area of wire
Wire is doubled so length will be doubled.
Let's assume R initial resistance..
R'= new resistance
R'=(2pl)/a
R'=2R
R'=2*4=8 ohm
New resistance is 8 ohm
_______________________________________
short way :-
f a 4 ohm resistance wire is doubled and connected in series 4 +4 =8 ohms it will be
,or if it is connected in parallel it will be 1/4+1/4 =2 ohms
.as per the formula R =r1 +r 2 if they are connected in series,
if they are connected in parallel, 1 /R =1 /r1 +1/r2.
_________________________________________
related questions❤
- If a wire has a resistance of 4 ohms and is doubled by folding it, what will be its new resistance?
- A wire of resistance is doubled on itself, then what is its new resistance?
- The wire of resistance 16 ohm. It is melted and drawn into a wire of half its length. Calculate the resistance of the new wire. What is the percentage change in its resistance?
- A piece of resistance wire has a resistance of 4 ohm. Its diameter is doubled. What is its new resistance?
- A wire of resistance 16 ohms is elongated to double its length. What is the new resistance?
- A wire of length 'l' is doubled on itself. What is the new resistance?
- If a 12-ohm resistance wire is doubled by itself, what will be the new resistance?
- A wire of resistance is one ohm and is stretched to double its length. What is the new resistance?
- A uniform wire of resistance 100 ohm is melted and recast in a wire of a length double that of the original. What is the new resistance of the wire?
_____________________________________
hope it helps
:)