Physics, asked by aasthaporwal47, 9 months ago

The resistance of a wire is 4 ohm. Calculate its new resistance if the radius of the wire is one-third of the original wire




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Answers

Answered by ıtʑFᴇᴇʟɓᴇãᴛ
4

\mathtt{\huge{\underline{\red{Question\:?}}}}

The resistance of a wire is 4 ohm. Calculate its new resistance if the radius of the wire is one-third of the original wire ?

\mathtt{\huge{\underline{\green{Answer:-}}}}

The new resistance of wire is 12 Ω .

\mathtt{\huge{\underline{\pink{Solution:-}}}}

Given :-

  • The resistance of a wire is 4 ohm.

  • The radius of the wire is one-third of the original wire.

To Find :-

  • The new resistance of wire.

Theory Involved :-

Resistance of a conductor is the property by virtue of which it opposes the charge through it.

R =  \dfrac{V}{I}

S.I. unit of resistance :- 1 Ω = 1 VA-¹

The resistance of conductor is directly proportional to its length;

R ∝ l .......... (1)

The resistance of conductor is inversely proportional to its area of cross section ;

R ∝  \dfrac{l}{a} ........... (2)

From 1 & 2 ,

R = p  \</em></strong><strong><em>d</em></strong><strong><em>frac</em></strong><strong><em>{l}{a}

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Calculation :-

According to the question,

The resistance of wire = 4 Ω

Let the area be r;

So, The Area of cross-section = r

Using resistivity Formula;

R = p  \frac{l}{a}

➡ 4 = p  \frac{l}{r}

➡ 4 r = p I

➡ I = 4r/p

Now,

The radius of the wire is one-third of the original wire. So, new resistance

When R = 1/3 r,

=> R = p. l/a

=> R = p . 4r/a

=> R = p . 4r/pa

=> R = 4r/a

We know,

Area a = r/3

=> R = 4r/r/3

=> R = 4× 3

=> R = 12

R = 12 Ω

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Attachments:
Answered by PixleyPanda
1

Answer:

Explanation:

Resistance= (pl)/a

l=length of wire

a=area of wire

Wire is doubled so length will be doubled.

Let's assume R initial resistance..

R'= new resistance

R'=(2pl)/a

R'=2R

R'=2*4=8 ohm

New resistance is 8 ohm

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short way :-

f a 4 ohm resistance wire is doubled and connected in series 4 +4 =8 ohms it will be

,or if it is connected in parallel it will be 1/4+1/4 =2 ohms

.as per the formula R =r1 +r 2 if they are connected in series,

if they are connected in parallel, 1 /R =1 /r1 +1/r2.

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hope it helps

:)

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