The resistance of a wire length 80 cm and uniform area of cross section 0.025cm^2 is found to be the resistance of 1.5ohms calculate the resistivity
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216
Here, resistance of the wire = R = 1.5
Ohm Cross sectional area = A = 0.025 cm2
Length of the wire = L = 80 cm
Since, resistivity = R x A/L = 1.5 x 0.025/80 = 4.687 x 10-4
Therefore, the resistivity of the wires = 4.687 x 10-4
Ohm Cross sectional area = A = 0.025 cm2
Length of the wire = L = 80 cm
Since, resistivity = R x A/L = 1.5 x 0.025/80 = 4.687 x 10-4
Therefore, the resistivity of the wires = 4.687 x 10-4
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helooo
Guys the correct answer is
resistance (R)= 1.5Ω
area of cross-section (A)= 0.025 cm²
= 0.025×10⁻⁴ m²
length (l)= 80 cm
= 0.8 m
Using R=ρl÷A
1.5 = ρ × 0.8 ÷ 0.025×10⁻⁴
ρ= 1.5 × 0.025×10⁻⁴ ÷ 0.8
= 0.047×10⁻⁴
= 4.7×10⁻⁶Ωm
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