Question

The resistance of a wire of length 10 m
is 2 ohm. If the area of cross section of the
wire is 2 x 10 m, determine its (i) resistivity
(ii) conductance and (iii) conductivity​

Answer 1

Answer:

CURRENT ELECTRICITY

Explanation:

★ GIVEN ★

» Length of Wire ( L ) = 10 m

★ Resistance of wire ( R ) = 2 Ω

★ Area of cross-Section ( A ) = 2 × 10-²

___________FIND OUT ____________

1 ] RESISTIVITY { p (rho) }

★ WE KNOW THAT ;

$r \: = p \: \times \frac{l}{a}$

★ p = R × A / l

» p = (2 × 2 × 10-² ) / 10

★» p = 4 × 10-³ { mho / ohm m-¹ } «★

♣ HENCE ; RESISTIVITY OF WIRE IS 4 × 10-³ mho.

________________________________________

2 ] CONDUCTIVITY { K }

★ WE KNOW THAT ;

$k \: = \frac{1}{p}$

So ;

» K = 1 / 4 × 10-³

★» K = 0.25 × 10³ = 250 { ohm / m } «★

→ Hence ; CONDUCTIVITY { K } of wire is [ 250 ohm / m. ] ←

________________________________________

3 ] CONDUCTANCE { C }

we know that ;

$c \: = \frac{1}{r}$

★» C = 1 / 2 = 0.5 { ohm-¹ } .

Hence ; CONDUCTANCE of wire is 0.5 ohm-¹.

♣ CONDUCTIVITY AND CONDUCTANCE ARE USED IN ELECTROCHEMICAL CELLS. ♥

Answer 2

$\bold {\huge {Your ~answer :-}}$

1. 4 × 10¯³ ohm.m
2. 0.5 ohm¯¹
3. 250 ohm/m

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Given—

》Length of wire (l) = 10 m

》Resistance of wire (R) = 2 ohm

》Area of cross section (A) = 2 × 10¯² m

To find -

》Resistivity (ꝭ) = ?

》Conductance (C) =?

》Conductivity (K) =?

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↪Actually welcome to the concept of current electricity

↪Basically we will use 3 different formulas

1●

=> $R =p \frac{l }{ A}$

=> $2 =p \frac{ 10}{2 \times10^{-2}}$

=> $p = \frac{ 4}{ 1000}$

⇒ꝭ = 4 × 10¯³

Hence the resistivity of wire is 4 × 10¯³ ohm.m

_______________________________

2●

C = 1/R

C = 1/2

C = 0.5

Hence, the Conductance of wire is 0.5 ohm¯¹

_____________________________

3●

K = 1/ꝭ

K = 1/4 × 10³ = 0.25 × 10³

K= 250

Hence, the Conductivity of wire is 250 ohm/m

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