The resistance of an electric heater is25ohm .its end are connected to the pole of a 90 v dry battery.how much current will flow in the heater wire?
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given resistance of heater as 25 ohms
potential difference =90v
electric current = v/r
hence i= 90v/25 ohm=3.6 ampere
potential difference =90v
electric current = v/r
hence i= 90v/25 ohm=3.6 ampere
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Answer:
ABOVE ANSWER is right really
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