Question

The resistance of copper wire of resistivity 0.00314, if it's length, is 1 m and its diameter is 2 mm is

Answer 1

Answer:

R = rho* l / a

= 0.00314 * 1m / π * 0.001 m * 0.001 m

= approx. 99.99 ohms.

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Answer 2

Answer:5.4×10^-3ohm

Explanation:length of wire L=1m

Diameter of wire d=2mm=2×10^-3m

Cross sectional area of wire

A=(pie × d^2)/4

=[3.14×(2×10^-3)^2]/4

A=3.14×10^-6 metre square

Specific resistance of copper p=1.69×10^-8 ohm metre

Now, R=p×L/A=1.69×10^-8 × 1/3.14×10^-6

R=0.54×10^-2 ohm or 5.4×10^-3 ohm